Unit 2 Day 3: Factoring Polynomials (GCF)

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Unit 2: Polynomial Operations

Day 3: Factoring Polynomials (GCF)

Lesson Objective

To be able to factor polynomials by finding and dividing out the Greatest Common Factor (GCF).

Warm-Up: Reverse The Action!

Yesterday, we learned how to multiply. Today, we learn how to do the reverse!

\(5(x + 3) \iff 5x + 15\)

Factoring is the process of finding what you multiplied to get an expression.

What is the GCF?

The Greatest Common Factor is the largest number and/or variable that divides evenly into all terms of the polynomial.

How to Find the GCF:

  1. Find the greatest common factor of the coefficients (the numbers).
  2. Find the greatest common factor of the variables (it's the variable with the lowest exponent).
  3. Multiply them together.

I Do: Finding the GCF

Let's find the GCF of \(12x^3 + 18x^2\).

Coefficients: The GCF of 12 and 18 is 6.

Variables: We have \(x^3\) and \(x^2\). The one with the lowest exponent is \(x^2\). The GCF is \(x^2\).


The GCF of the whole polynomial is \(6x^2\).

I Do: Factoring out the GCF

Now, let's factor \(12x^3 + 18x^2\).

// Step 1: We found the GCF is \(6x^2\). Put it outside the parentheses.

\(6x^2(\quad ? \quad + \quad ? \quad)\)

// Step 2: Divide each original term by the GCF.

\(\frac{12x^3}{6x^2} = 2x \quad \text{and} \quad \frac{18x^2}{6x^2} = 3\)

// Step 3: Put the results inside the parentheses.

\(6x^2(2x + 3)\)

Check your answer: Distribute \(6x^2(2x+3)\) to see if you get back to \(12x^3 + 18x^2\)!

We Do: Let's Try Together

Let's factor this trinomial as a class.

\(8a^3 - 4a^2 + 12a\)

Hint: What is the GCF of 8, -4, and 12? What is the GCF of \(a^3, a^2,\) and \(a\)?

You Do: On Your Own

Factor the following polynomial completely.

\(5y^3 - 10y^2\)

\(5y^2(y - 2)\)

Independent Practice

Try these problems on your handout, starting with green.

Green Level

FACTOR: \(4x + 8\)

Yellow Level

FACTOR: \(3n^2 - 9n + 15\)

Red Level

FACTOR: \(14p^4 - 21p^3 + 7p^2\)

Exit Ticket

On your handout or a piece of paper, factor the following expression completely:

\(18m^2 + 6m\)